fix: Useing 'type' instad of 'which', which is more robust
For reference, see: https://stackoverflow.com/questions/592620/check-if-a-program-exists-from-a-bash-script.
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@ -10,7 +10,7 @@ TEXT_COLOR="\e[0;35m"
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COLON_COLOR="\e[0;35m"
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END_COLOR="\e[m"
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if [[ -x `which curl` ]]; then
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if $(type curl > /dev/null); then
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function quote()
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{
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Q=$(curl -s --connect-timeout 2 "http://www.quotationspage.com/random.php3" | iconv -c -f ISO-8859-1 -t UTF-8 | grep -m 1 "dt ")
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